1.3 Bases

  • Definitions. Let \(\lst {v}1n\) be a list of vectors in a vector space \(V\).

    • (1) The span of \(\lst {v}1n\) is

      \begin{equation*} \Span {\lst {v}1n}:=\set {\lc \lambda {v}1n\st \lambda _i\in \F , 1\leq i\leq n}\leq V. \end{equation*}

    • (2) \(\lst {v}1n\) span \(V\) (or are a spanning list for \(V\)) if \(\Span {\lst {v}1n}=V\).

    • (3) \(\lst {v}1n\) are linearly independent if, whenever \(\lc \lambda {v}1n=0\), then each \(\lambda _i=0\), \(1\leq i\leq n\), and linearly dependent otherwise.

    • (4) \(\lst {v}1n\) is a basis for \(V\) if they are linearly independent and span \(V\).

  • Definition. A vector space is finite-dimensional if it admits a finite list of vectors as basis and infinite-dimensional otherwise.

    If \(V\) is finite-dimensional, the dimension of \(V\), \(\dim V\), is the number of vectors in a (any) basis of \(V\).

1.3.1 Useful facts
  • Proposition 1.1 (Algebra 1B, Corollary 1.4.7). Any linearly independent list of vectors in a finite-dimensional vector space can be extended to a basis.

  • Proposition 1.2 (Algebra 1B, Corollary 1.4.6). Let \(V\) be a finite-dimensional vector space and \(U\leq V\). Then

    \begin{equation*} \dim U\leq \dim V \end{equation*}

    with equality if and only if \(U=V\).